What is the domain of f(x)=ln((x+1)/(x-1)) ?

The domain of f(x)=ln((x+1)/(x-1)) is x 1

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domain of f(x)=ln((x+1)/(x-1))

domain

f (x) = ln (\frac{x + 1}{x - 1})

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

y = x^{2} - 6 x

\frac{2 x ^{2} + 3 x - 2}{x - 2}

\frac{x ^{2} - 81}{x ( x - 9 )}

(4, 6), (- 3, - 7)

f (x) = - 2 x^{2} - 2 x + 30

What is the domain of f(x)=ln((x+1)/(x-1)) ?
The domain of f(x)=ln((x+1)/(x-1)) is x<-1\lor x>1