What is the inverse of f(x)=\sqrt[3]{x-6}+8 ?

The inverse of f(x)=\sqrt[3]{x-6}+8 is x^3-24x^2+192x-506

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[3]{x-6}+8

inverse

x^{3} - 24 x^{2} + 192 x - 506

Solution steps

Replace

x

with

y

Solve for

x^{3} - 24 x^{2} + 192 x - 506

f (x) = \frac{6}{x - 4}

f (x) = \frac{15}{x + 14}

(7.2) (7.5)

\frac{( \frac{1}{x} )}{x ^{2} - 4}

f (x) = 4 - 4 x^{2}

What is the inverse of f(x)=\sqrt[3]{x-6}+8 ?
The inverse of f(x)=\sqrt[3]{x-6}+8 is x^3-24x^2+192x-506