What is the domain of f(x)= 1/(sqrt(x^2-2x-8)) ?

The domain of f(x)= 1/(sqrt(x^2-2x-8)) is x 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(sqrt(x^2-2x-8))

domain

f (x) = \frac{1}{x ^{2} - 2 x - 8}

x < - 2 or x > 4

Interval Notation

(- \infty, - 2) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 4

Find undefined (singularity) points:

x = 4, x = - 2

Combine real regions and undefined points for final function domain

x < - 2 or x > 4

f (x) = x^{4} - 4 x^{3}

f (x) = 3 x^{4} + 8 x^{3}

y = 2 x + 1

f (x) = 6 tan (π x)

lo g_{10} (x)

What is the domain of f(x)= 1/(sqrt(x^2-2x-8)) ?
The domain of f(x)= 1/(sqrt(x^2-2x-8)) is x<-2\lor x>4