en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=sqrt(2x^2+4)

Solution

f (x) = 2 x^{2} + 4

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 2

Y Intercepts : (0, 2)

Asymptotes : Slant y = 2 x, y = - 2 x

Extreme Points : Minimum (0, 2)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [2, \infty)

Solution steps

Domain of

2 x^{2} + 4 : - \infty < x < \infty

Range of

2 x^{2} + 4 : f (x) \geq 2

Axis interception points of

2 x^{2} + 4 :

Y Intercepts

: (0, 2)

Asymptotes of

2 x^{2} + 4 :

Slant

: y = 2 x, y = - 2 x

Extreme Points of

2 x^{2} + 4 :

Minimum

(0, 2)

Popular Examples

f(x)=sqrt(2x^2-1)

f (x) = 2 x^{2} - 1

f(x)=sin^6(x)+cos^6(x)+3sin^2(x)cos^2(x)

f (x) = sin^{6} (x) + cos^{6} (x) + 3 sin^{2} (x) cos^{2} (x)

f(x)=(x^2)/((x^2+1))

f (x) = \frac{x ^{2}}{( x ^{2} + 1 )}

f(x)=2sin(2x)+1

f (x) = 2 sin (2 x) + 1

solvefor r,r=7sec(θ)solve for

r, r = 7 sec (θ)

Frequently Asked Questions (FAQ)

What is the f(x)=sqrt(2x^2+4) ?
The f(x)=sqrt(2x^2+4) is