What is the f(t)=-0.083t^3+0.29t^2+1.241t+0.03 ?

The f(t)=-0.083t^3+0.29t^2+1.241t+0.03 is

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f(t)=-0.083t^3+0.29t^2+1.241t+0.03

f (t) = - 0.083 t^{3} + 0.29 t^{2} + 1.241 t + 0.03

Domain : - \infty < t < \infty

Range : - \infty < f (t) < \infty

X Intercepts : (- 0.02431 \dots, 0), (- 2.47888 \dots, 0), (5.99716 \dots, 0), Y Intercepts : (0, 0.03)

Asymptotes : None

Extreme Points : Minimum (- \frac{- 290 + 393109}{249}, - 0.91262 \dots), Maximum (\frac{290 + 393109}{249}, 4.38778 \dots)

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

- 0.083 t^{3} + 0.29 t^{2} + 1.241 t + 0.03 : - \infty < t < \infty

Range of

- 0.083 t^{3} + 0.29 t^{2} + 1.241 t + 0.03 : - \infty < f (t) < \infty

Axis interception points of

- 0.083 t^{3} + 0.29 t^{2} + 1.241 t + 0.03 :

X Intercepts

: (- 0.02431 \dots, 0), (- 2.47888 \dots, 0), (5.99716 \dots, 0),

Y Intercepts

: (0, 0.03)

Asymptotes of

- 0.083 t^{3} + 0.29 t^{2} + 1.241 t + 0.03 :

None

Extreme Points of

- 0.083 t^{3} + 0.29 t^{2} + 1.241 t + 0.03 :

Minimum

(- \frac{- 290 + 393109}{249}, - 0.91262 \dots),

Maximum

(\frac{290 + 393109}{249}, 4.38778 \dots)

f (x) = 5 - ∣ x ∣

y = 2 x - 6 - 1

f (4) = x^{2} + 3 x - 4

f (x) = 6 e^{- x}

f (x) = x^{0.6}

What is the f(t)=-0.083t^3+0.29t^2+1.241t+0.03 ?
The f(t)=-0.083t^3+0.29t^2+1.241t+0.03 is