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Popular >

h(t)=32t-16t^2

Solution

h (t) = 32 t - 16 t^{2}

Solution

Domain : - \infty < t < \infty

Range : f (t) \leq 16

X Intercepts : (0, 0), (2, 0), Y Intercepts : (0, 0)

Vertex : Maximum (1, 16)

Inverse : - \frac{- 4 + - t + 16}{4}, \frac{- t + 16 + 4}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

32 t - 16 t^{2} : - \infty < t < \infty

Range of

32 t - 16 t^{2} : f (t) \leq 16

Axis interception points of

32 t - 16 t^{2} :

X Intercepts

: (0, 0), (2, 0),

Y Intercepts

: (0, 0)

Vertex of

32 t - 16 t^{2} :

Maximum

(1, 16)

Inverse of

32 t - 16 t^{2} : - \frac{- 4 + - t + 16}{4}, \frac{- t + 16 + 4}{4}

Graph

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Frequently Asked Questions (FAQ)

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