What is the midpoint (-2/3 , 1/3),(-16/3 ,-7/3) ?

The midpoint (-2/3 , 1/3),(-16/3 ,-7/3) is (-3,-1)

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midpoint (-2/3 , 1/3),(-16/3 ,-7/3)

midpoint

(- \frac{2}{3}, \frac{1}{3}), (- \frac{16}{3}, - \frac{7}{3})

(- 3, - 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- \frac{2}{3}, \frac{1}{3}), (x_{2}, y_{2}) = (- \frac{16}{3}, - \frac{7}{3})

= (\frac{- \frac{16}{3} - \frac{2}{3}}{2}, \frac{- \frac{7}{3} + \frac{1}{3}}{2})

Refine

= (- 3, - 1)

f (x) = - 2 x + 8 y = - 24

f (x) = 9 x + 7

f (x) = - (x + 1)^{2} + 3

f (x) = \frac{6}{x + 5}

f (x) = 2 t

What is the midpoint (-2/3 , 1/3),(-16/3 ,-7/3) ?
The midpoint (-2/3 , 1/3),(-16/3 ,-7/3) is (-3,-1)