What is the critical f(x)=-16t^2+60t+3 ?

The critical f(x)=-16t^2+60t+3 is t= 15/8

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critical f(x)=-16t^2+60t+3

critical points

f (x) = - 16 t^{2} + 60 t + 3

t = \frac{15}{8}

Solution steps

- 16 t^{2} + 60 t + 3

Find where

f^{'} (t)

is equal to zero or undefined

t = \frac{15}{8}

Identify critical points not in

f (t)

domain

Domain of

- 16 t^{2} + 60 t + 3 : - \infty < t < \infty

All critical points are in domain

t = \frac{15}{8}

f (x) = \frac{8 + x}{x + 9}

x^{2} + 8

\frac{4}{x ^{2} - 9}

f (x) = 3 (12 - x)

5 x - 2 y = 0

What is the critical f(x)=-16t^2+60t+3 ?
The critical f(x)=-16t^2+60t+3 is t= 15/8