What is the f(x)=6x^2-8x+3 ?

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f(x)=6x^2-8x+3

f (x) = 6 x^{2} - 8 x + 3

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{1}{3}

Y Intercepts : (0, 3)

Vertex : Minimum (\frac{2}{3}, \frac{1}{3})

Inverse : \frac{8 + 24 x - 8}{12}, \frac{8 - 24 x - 8}{12}

Interval Notation

Domain : (- \infty, \infty)

Range : [\frac{1}{3}, \infty)

Solution steps

Domain of

6 x^{2} - 8 x + 3 : - \infty < x < \infty

Range of

6 x^{2} - 8 x + 3 : f (x) \geq \frac{1}{3}

Axis interception points of

6 x^{2} - 8 x + 3 :

Y Intercepts

: (0, 3)

Vertex of

6 x^{2} - 8 x + 3 :

Minimum

(\frac{2}{3}, \frac{1}{3})

Inverse of

6 x^{2} - 8 x + 3 : \frac{8 + 24 x - 8}{12}, \frac{8 - 24 x - 8}{12}

y = \frac{1 0 ^{x} - 1 0 ^{- x}}{1 0 ^{x} + 1 0 ^{- x}}

f (x) = \frac{1}{5} x^{3} + x^{2} - 2 x

y = x^{3} - 3 x^{2} - 26 x - 24

f (x) = \frac{x - 4}{x + 1}

f (x) = 1 - lo g_{5} (x - 2)