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Popular >

y=2x^2+2x+1

Solution

y = 2 x^{2} + 2 x + 1

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{1}{2}

Y Intercepts : (0, 1)

Vertex : Minimum (- \frac{1}{2}, \frac{1}{2})

Inverse : \frac{- 1 + 2 x - 1}{2}, - \frac{2 x - 1 + 1}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [\frac{1}{2}, \infty)

Solution steps

Domain of

2 x^{2} + 2 x + 1 : - \infty < x < \infty

Range of

2 x^{2} + 2 x + 1 : f (x) \geq \frac{1}{2}

Axis interception points of

2 x^{2} + 2 x + 1 :

Y Intercepts

: (0, 1)

Vertex of

2 x^{2} + 2 x + 1 :

Minimum

(- \frac{1}{2}, \frac{1}{2})

Inverse of

2 x^{2} + 2 x + 1 : \frac{- 1 + 2 x - 1}{2}, - \frac{2 x - 1 + 1}{2}

Popular Examples

f(x)=sqrt(x-1)-1

f (x) = x - 1 - 1

f (x) = x^{2} - 6 + 5

solvefor r,r=5-5cos(θ)solve for

r, r = 5 - 5 cos (θ)

f (x) = \frac{9}{x ^{3}}

f(m)=(m^{1/2}-1)/(m^{1/2)+1}

f (m) = \frac{m ^{\frac{1}{2}} - 1}{m ^{\frac{1}{2}} + 1}

Frequently Asked Questions (FAQ)

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