What is the F(s)=((7s-1))/([(s+1)(s+2)(s-3)]) ?

The F(s)=((7s-1))/([(s+1)(s+2)(s-3)]) is

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F(s)=((7s-1))/([(s+1)(s+2)(s-3)])

F (s) = \frac{( 7 s - 1 )}{[ ( s + 1 ) ( s + 2 ) ( s - 3 ) ]}

Domain : s < - 2 or - 2 < s < - 1 or - 1 < s < 3 or s > 3

Range : - \infty < f (s) < \infty

X Intercepts : (\frac{1}{7}, 0), Y Intercepts : (0, \frac{1}{6})

Asymptotes : Vertical s = - 2, s = - 1, s = 3, Horizontal y = 0

Extreme Points : Maximum (- 1.45012 \dots, - 10.12370 \dots)

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, - 1) \cup (- 1, 3) \cup (3, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{7 s - 1}{( s + 1 ) ( s + 2 ) ( s - 3 )} : s < - 2 or - 2 < s < - 1 or - 1 < s < 3 or s > 3

Range of

\frac{7 s - 1}{( s + 1 ) ( s + 2 ) ( s - 3 )} : - \infty < f (s) < \infty

Axis interception points of

\frac{7 s - 1}{( s + 1 ) ( s + 2 ) ( s - 3 )} :

X Intercepts

: (\frac{1}{7}, 0),

Y Intercepts

: (0, \frac{1}{6})

Asymptotes of

\frac{7 s - 1}{( s + 1 ) ( s + 2 ) ( s - 3 )} :

Vertical

: s = - 2, s = - 1, s = 3,

Horizontal

: y = 0

Extreme Points of

\frac{7 s - 1}{( s + 1 ) ( s + 2 ) ( s - 3 )} :

Maximum

(- 1.45012 \dots, - 10.12370 \dots)

y = x^{3} e^{- x^{2}}

f (x) = - x^{2} + 10 x + 2

f (x) = 0.25

f (t) = 3 cos (2 t) + 4 sin (2 t)

f (x) = \frac{sin ( x - π )}{cos ( x - \frac{π}{2} )}

What is the F(s)=((7s-1))/([(s+1)(s+2)(s-3)]) ?
The F(s)=((7s-1))/([(s+1)(s+2)(s-3)]) is