What is the domain of ln((x^2-1)/(x^5)),x>1 ?

The domain of ln((x^2-1)/(x^5)),x>1 is x>1

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domain of ln((x^2-1)/(x^5)),x>1

domain

ln (\frac{x ^{2} - 1}{x ^{5}}), x > 1

x > 1

Interval Notation

(1, \infty)

Solution steps

Set the domain to the given interval

x > 1

Find positive values for logs:

- 1 < x < 0 or x > 1

Find undefined (singularity) points:

No real undefined points

Join with the domain:

(- 1 < x < 0 or x > 1) and x > 1

x > 1

f (x) = 2 ln (x + 2)

f (x) = x^{4} - 8 x^{2} + 12

f (x) = sin (4 x) - cos (4 x)

f (t) = t e^{- 2 t}

f (t) = (2 t - 1)^{3}

What is the domain of ln((x^2-1)/(x^5)),x>1 ?
The domain of ln((x^2-1)/(x^5)),x>1 is x>1