What is the y= x/(sqrt(x^2+1)),0<= x<= 1 ?

The y= x/(sqrt(x^2+1)),0<= x<= 1 is

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y= x/(sqrt(x^2+1)),0<= x<= 1

y = \frac{x}{x ^{2} + 1}, 0 \leq x \leq 1

Domain : 0 \leq x \leq 1

Range : 0 \leq f (x) \leq \frac{1}{2}

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Minimum (0, 0), Maximum (1, \frac{1}{2})

Interval Notation

Domain : [0, 1]

Range : [0, \frac{1}{2}]

Solution steps

Domain of

\frac{x}{x ^{2} + 1}, 0 \leq x \leq 1 : 0 \leq x \leq 1

Range of

\frac{x}{x ^{2} + 1}, 0 \leq x \leq 1 : 0 \leq f (x) \leq \frac{1}{2}

Axis interception points of

\frac{x}{x ^{2} + 1}, 0 \leq x \leq 1 :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{x}{x ^{2} + 1}, 0 \leq x \leq 1 :

None

Extreme Points of

\frac{x}{x ^{2} + 1}, 0 \leq x \leq 1 :

Minimum

(0, 0),

Maximum

(1, \frac{1}{2})

y = ln (\frac{2}{x})

f (x) = \frac{e ^{x}}{e ^{x} - 1}

y = 3 x^{2} - 4 x + 5

f (x) = 2^{2 x - 1} + 3

y = 1 + 2 x