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Popular >

distance (-4,-2),(-5,-6)

Solution

distance

(- 4, - 2), (- 5, - 6)

Solution

17

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 4, - 2)

and

(- 5, - 6)

is

= (- 5 - (- 4))^{2} + (- 6 - (- 2))^{2}

Simplify

= 17

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s (t) = \frac{4 t}{sin ( t )}

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f (x) = 7 x + 5

critical sqrt((x^2-4)^2)critical points

(x^{2} - 4)^{2}

parity f(x)=(-(8pi)/(11))parity

f (x) = (- \frac{8 π}{11})

extreme f(x)=e^{3x}+e^{-3x}extreme points

f (x) = e^{3 x} + e^{- 3 x}

Frequently Asked Questions (FAQ)

What is the distance (-4,-2),(-5,-6) ?
The distance (-4,-2),(-5,-6) is square root of 17