What is the general solution for solvefor r,r=(18)/(1-cos(θ)) ?

The general solution for solvefor r,r=(18)/(1-cos(θ)) is r=(18)/(1-cos(θ))

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solvefor r,r=(18)/(1-cos(θ))

solve for

r, r = \frac{18}{1 - cos ( θ )}

r = \frac{18}{1 - cos ( θ )}

Solution steps

r = \frac{18}{1 - cos ( θ )}

Could not simplify further

r = \frac{18}{1 - cos ( θ )}

f (x) = 6 (x - 1) + 9

f (x) = arccos (2 x - 1)

f (x) = - 2 x^{2} - 8 x - 10

f (x) = \frac{3 - 6 x + 21}{x + 2}

f (x) = x^{4} - 8 x^{2} + 5

What is the general solution for solvefor r,r=(18)/(1-cos(θ)) ?
The general solution for solvefor r,r=(18)/(1-cos(θ)) is r=(18)/(1-cos(θ))