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Popular >

U(t)=1.2t^2+4t-8

Solution

U (t) = 1.2 t^{2} + 4 t - 8

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq - 11.33333 \dots

X Intercepts : (\frac{- 5 + 85}{3}, 0), (- \frac{5 + 85}{3}, 0), Y Intercepts : (0, - 8)

Vertex : Minimum (- 1.66666 \dots, - 11.33333 \dots)

Inverse : \frac{- 40 + 480 t + 5440}{24}, \frac{- 40 - 480 t + 5440}{24}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- 11.33333 \dots, \infty)

Solution steps

Domain of

1.2 t^{2} + 4 t - 8 : - \infty < t < \infty

Range of

1.2 t^{2} + 4 t - 8 : f (t) \geq - 11.33333 \dots

Axis interception points of

1.2 t^{2} + 4 t - 8 :

X Intercepts

: (\frac{- 5 + 85}{3}, 0), (- \frac{5 + 85}{3}, 0),

Y Intercepts

: (0, - 8)

Vertex of

1.2 t^{2} + 4 t - 8 :

Minimum

(- 1.66666 \dots, - 11.33333 \dots)

Inverse of

1.2 t^{2} + 4 t - 8 : \frac{- 40 + 480 t + 5440}{24}, \frac{- 40 - 480 t + 5440}{24}

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Frequently Asked Questions (FAQ)

What is the U(t)=1.2t^2+4t-8 ?
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