What is the f(x)=(e^x+e^{-2x})/(e^x-2e^{-x)} ?

The f(x)=(e^x+e^{-2x})/(e^x-2e^{-x)} is

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f(x)=(e^x+e^{-2x})/(e^x-2e^{-x)}

f (x) = \frac{e ^{x} + e ^{- 2 x}}{e ^{x} - 2 e ^{- x}}

Domain : x < \frac{ln ( 2 )}{2} or x > \frac{ln ( 2 )}{2}

Range : - \infty < f (x) < \infty

Y Intercepts : (0, - 2)

Asymptotes : Vertical x = \frac{ln ( 2 )}{2}, Horizontal y = 1

Extreme Points : Maximum (ln (0.60700 \dots), - 1.23556 \dots)

Interval Notation

Domain : (- \infty, \frac{ln ( 2 )}{2}) \cup (\frac{ln ( 2 )}{2}, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{e ^{x} + e ^{- 2 x}}{e ^{x} - 2 e ^{- x}} : x < \frac{ln ( 2 )}{2} or x > \frac{ln ( 2 )}{2}

Range of

\frac{e ^{x} + e ^{- 2 x}}{e ^{x} - 2 e ^{- x}} : - \infty < f (x) < \infty

Axis interception points of

\frac{e ^{x} + e ^{- 2 x}}{e ^{x} - 2 e ^{- x}} :

Y Intercepts

: (0, - 2)

Asymptotes of

\frac{e ^{x} + e ^{- 2 x}}{e ^{x} - 2 e ^{- x}} :

Vertical

: x = \frac{ln ( 2 )}{2},

Horizontal

: y = 1

Extreme Points of

\frac{e ^{x} + e ^{- 2 x}}{e ^{x} - 2 e ^{- x}} :

Maximum

(ln (0.60700 \dots), - 1.23556 \dots)

f (x) = ln (sin (x))

f (x) = x (x - 7)^{2} (x + 3)^{2}

f (x) = 2 x^{2} - 6 x - 5

y = - 0.12 x^{2} + 168 x + 200

f (x) = \frac{5 x}{x ^{2} - 25}

What is the f(x)=(e^x+e^{-2x})/(e^x-2e^{-x)} ?
The f(x)=(e^x+e^{-2x})/(e^x-2e^{-x)} is