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Popular >

f(t)=ln(1+t^2)

Solution

f (t) = ln (1 + t^{2})

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq 0

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Minimum (0, 0)

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Interval Notation

Domain : (- \infty, \infty)

Range : [0, \infty)

Solution steps

Domain of

ln (1 + t^{2}) : - \infty < t < \infty

Range of

ln (1 + t^{2}) : f (t) \geq 0

Axis interception points of

ln (1 + t^{2}) :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

ln (1 + t^{2}) :

None

Extreme Points of

ln (1 + t^{2}) :

Minimum

(0, 0)

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Frequently Asked Questions (FAQ)

What is the f(t)=ln(1+t^2) ?
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