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Popular >

f(2)=((3x)/(2+2x-x^2))^2

Solution

f (2) = (\frac{3 x}{2 + 2 x - x ^{2}})^{2}

Solution

Domain : x < 1 - 3 or 1 - 3 < x < 1 + 3 or x > 1 + 3

Range : f (x) \geq 0

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = 1 - 3, x = 1 + 3, Horizontal y = 0

Extreme Points : Minimum (0, 0)

+1

Interval Notation

Domain : (- \infty, 1 - 3) \cup (1 - 3, 1 + 3) \cup (1 + 3, \infty)

Range : [0, \infty)

Solution steps

Domain of

(\frac{3 x}{2 + 2 x - x ^{2}})^{2} : x < 1 - 3 or 1 - 3 < x < 1 + 3 or x > 1 + 3

Range of

(\frac{3 x}{2 + 2 x - x ^{2}})^{2} : f (x) \geq 0

Axis interception points of

(\frac{3 x}{2 + 2 x - x ^{2}})^{2} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

(\frac{3 x}{2 + 2 x - x ^{2}})^{2} :

Vertical

: x = 1 - 3, x = 1 + 3,

Horizontal

: y = 0

Extreme Points of

(\frac{3 x}{2 + 2 x - x ^{2}})^{2} :

Minimum

(0, 0)

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Frequently Asked Questions (FAQ)

What is the f(2)=((3x)/(2+2x-x^2))^2 ?
The f(2)=((3x)/(2+2x-x^2))^2 is