What is the domain of f(x)=sqrt(x^2+4) ?

The domain of f(x)=sqrt(x^2+4) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+4)

domain

f (x) = x^{2} + 4

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

5 - x

f (x) = 3 x^{2}

f (x) = 3 x^{2} + 2 x - 1

f (x) = \frac{2 x + 4}{x ^{2} + 2 x - 8}

f (x) = 2 cos (3 x - π)

What is the domain of f(x)=sqrt(x^2+4) ?
The domain of f(x)=sqrt(x^2+4) is -infinity <x<infinity