What is the derivative of 4sec(pi/4 (x+1)) ?

The derivative of 4sec(pi/4 (x+1)) is pisec(pi/4 (x+1))tan(pi/4 (x+1))

What is the first derivative of 4sec(pi/4 (x+1)) ?

The first derivative of 4sec(pi/4 (x+1)) is pisec(pi/4 (x+1))tan(pi/4 (x+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (4 sec (\frac{π}{4} (x + 1)))

π sec (\frac{π}{4} (x + 1)) tan (\frac{π}{4} (x + 1))

Solution steps

\frac{d}{d x} (4 sec (\frac{π}{4} (x + 1)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (sec (\frac{π}{4} (x + 1)))

Apply the chain rule:

sec (\frac{π}{4} (x + 1)) tan (\frac{π}{4} (x + 1)) \frac{d}{d x} (\frac{π}{4} (x + 1))

= sec (\frac{π}{4} (x + 1)) tan (\frac{π}{4} (x + 1)) \frac{d}{d x} (\frac{π}{4} (x + 1))

\frac{d}{d x} (\frac{π}{4} (x + 1)) = \frac{π}{4}

= 4 sec (\frac{π}{4} (x + 1)) tan (\frac{π}{4} (x + 1)) \frac{π}{4}

Simplify

4 sec (\frac{π}{4} (x + 1)) tan (\frac{π}{4} (x + 1)) \frac{π}{4} : π sec (\frac{π}{4} (x + 1)) tan (\frac{π}{4} (x + 1))

= π sec (\frac{π}{4} (x + 1)) tan (\frac{π}{4} (x + 1))

y = \frac{3 x}{2}

y = 2 cos (x) - 1

f (x) = - 3 x^{2} + 4 x + 1

f (x) = x^{5} cos (x)

f (x) = x - ln (1 + x^{2})

What is the derivative of 4sec(pi/4 (x+1)) ?
The derivative of 4sec(pi/4 (x+1)) is pisec(pi/4 (x+1))tan(pi/4 (x+1))
What is the first derivative of 4sec(pi/4 (x+1)) ?
The first derivative of 4sec(pi/4 (x+1)) is pisec(pi/4 (x+1))tan(pi/4 (x+1))