What is the f(x)=4x^2+4arccos(x) ?

The f(x)=4x^2+4arccos(x) is Domain:-1 Y Intercepts: (0,2pi) Asymptotes: None

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f(x)=4x^2+4arccos(x)

f (x) = 4 x^{2} + 4 arccos (x)

Domain : - 1 \leq x \leq 1

Y Intercepts : (0, 2 π)

Asymptotes : None

Interval Notation

Domain : [- 1, 1]

Solution steps

Domain of

4 x^{2} + 4 arccos (x) : - 1 \leq x \leq 1

Axis interception points of

4 x^{2} + 4 arccos (x) :

Y Intercepts

: (0, 2 π)

Asymptotes of

4 x^{2} + 4 arccos (x) :

None

f (x) = \frac{5}{6 x}

x^{2} - 2 x + 1

f (t) = t^{2} - 4 t + 8

f (x) = \frac{x + 3}{x ^{2} - 1}

f (t) = e^{2 t} + 2 + e^{- 2 t}

What is the f(x)=4x^2+4arccos(x) ?
The f(x)=4x^2+4arccos(x) is Domain:-1<= x<= 1<br/>Y Intercepts: (0,2pi)<br/>Asymptotes: None