What is the domain of f(x)=((10x^2-3)^4)/((3x^3+8)^5) ?

The domain of f(x)=((10x^2-3)^4)/((3x^3+8)^5) is x -2/(\sqrt[3]{3)}

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domain of f(x)=((10x^2-3)^4)/((3x^3+8)^5)

domain

f (x) = \frac{( 10 x ^{2} - 3 ) ^{4}}{( 3 x ^{3} + 8 ) ^{5}}

Interval Notation

Solution steps

Find undefined (singularity) points:

The function domain

f (x) = - 0.01 x^{2} + 0.7 x + 6.1

f (x) = \frac{x ^{2} + 5 x}{- 2 x ^{2} + 7 x}

f (x) = - x^{2} + 8 x + 7

f (x) = - \frac{1}{ln ( x )}

f (x) = \frac{2 x ^{2} + 11 x + 5}{3 x + 15}

What is the domain of f(x)=((10x^2-3)^4)/((3x^3+8)^5) ?
The domain of f(x)=((10x^2-3)^4)/((3x^3+8)^5) is x<-2/(\sqrt[3]{3)}\lor x>-2/(\sqrt[3]{3)}