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Popular >

y=(x^2+1)/(x^3-1)

Solution

y = \frac{x ^{2} + 1}{x ^{3} - 1}

Solution

Domain : x < 1 or x > 1

Range : f (x) < 0 or f (x) > 0

Y Intercepts : (0, - 1)

Asymptotes : Vertical x = 1, Horizontal y = 0

Extreme Points : Minimum (- 0.59607 \dots, - 1.11843 \dots), Maximum (0, - 1)

+1

Interval Notation

Domain : (- \infty, 1) \cup (1, \infty)

Range : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{x ^{2} + 1}{x ^{3} - 1} : x < 1 or x > 1

Range of

\frac{x ^{2} + 1}{x ^{3} - 1} : f (x) < 0 or f (x) > 0

Axis interception points of

\frac{x ^{2} + 1}{x ^{3} - 1} :

Y Intercepts

: (0, - 1)

Asymptotes of

\frac{x ^{2} + 1}{x ^{3} - 1} :

Vertical

: x = 1,

Horizontal

: y = 0

Extreme Points of

\frac{x ^{2} + 1}{x ^{3} - 1} :

Minimum

(- 0.59607 \dots, - 1.11843 \dots),

Maximum

(0, - 1)

Popular Examples

y=log_{2}(-x+1)+2

y = lo g_{2} (- x + 1) + 2

f(x)=(2x-1)/(x^2-1)

f (x) = \frac{2 x - 1}{x ^{2} - 1}

f(x)=(x^3-9x)+(45-5x^2)

f (x) = (x^{3} - 9 x) + (45 - 5 x^{2})

f(x)=(cos(x))/(sec(x)-tan(x))

f (x) = \frac{cos ( x )}{sec ( x ) - tan ( x )}

f(x)=(x^4)/4-(x^3)/3-2x^2+4x+3

f (x) = \frac{x ^{4}}{4} - \frac{x ^{3}}{3} - 2 x^{2} + 4 x + 3

Frequently Asked Questions (FAQ)

What is the y=(x^2+1)/(x^3-1) ?
The y=(x^2+1)/(x^3-1) is