定义域 f(x)=(37)/((1-6x)^2)

解答

定义域

f (x) = \frac{37}{( 1 - 6 x ) ^{2}}

x < \frac{1}{6} or x > \frac{1}{6}

间隔符号

(- \infty, \frac{1}{6}) \cup (\frac{1}{6}, \infty)

求解步骤

找到无定义的点（奇点）:

x = \frac{1}{6}

函数定义域

x < \frac{1}{6} or x > \frac{1}{6}

y = 3 x + 4

f (x) = (x + 1)^{2} + 9

\frac{9}{8}

f (x) = \frac{5}{9}

f (x) = - \frac{9}{2 x ^{\frac{2}{3}}}