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Popular >

f(x)=(-1)/(x^2-9)

Solution

f (x) = \frac{- 1}{x ^{2} - 9}

Solution

Domain : x < - 3 or - 3 < x < 3 or x > 3

Range : f (x) < 0 or f (x) \geq \frac{1}{9}

Y Intercepts : (0, \frac{1}{9})

Asymptotes : Vertical x = - 3, x = 3, Horizontal y = 0

Extreme Points : Minimum (0, \frac{1}{9})

+1

Interval Notation

Domain : (- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Range : (- \infty, 0) \cup [\frac{1}{9}, \infty)

Solution steps

Domain of

\frac{- 1}{x ^{2} - 9} : x < - 3 or - 3 < x < 3 or x > 3

Range of

\frac{- 1}{x ^{2} - 9} : f (x) < 0 or f (x) \geq \frac{1}{9}

Axis interception points of

\frac{- 1}{x ^{2} - 9} :

Y Intercepts

: (0, \frac{1}{9})

Asymptotes of

\frac{- 1}{x ^{2} - 9} :

Vertical

: x = - 3, x = 3,

Horizontal

: y = 0

Extreme Points of

\frac{- 1}{x ^{2} - 9} :

Minimum

(0, \frac{1}{9})

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Frequently Asked Questions (FAQ)

What is the f(x)=(-1)/(x^2-9) ?
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