What is the extreme f(x)=x^3-9x^2 ?

The extreme f(x)=x^3-9x^2 is Maximum(0,0),Minimum(6,-108)

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extreme f(x)=x^3-9x^2

extreme points

f (x) = x^{3} - 9 x^{2}

Maximum (0, 0), Minimum (6, - 108)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{3} - 9 x^{2} : 0

Maximum (0, 0)

Plug

x = 6

into

x^{3} - 9 x^{2} : - 108

Minimum (6, - 108)

Maximum (0, 0), Minimum (6, - 108)

y = - 4 x - 8

f (x) = \frac{1}{x ^{2} - 4 x - 4}

2 x + y = 6

f (x) = \frac{4 x - 9}{2 x}

f (x) = 3 x + 45

What is the extreme f(x)=x^3-9x^2 ?
The extreme f(x)=x^3-9x^2 is Maximum(0,0),Minimum(6,-108)