What is the inverse of f(x)=((1+x^2))/((2+x^4)) ?

The inverse of f(x)=((1+x^2))/((2+x^4)) is

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inverse of f(x)=((1+x^2))/((2+x^4))

inverse

f (x) = \frac{( 1 + x ^{2} )}{( 2 + x ^{4} )}

\frac{1 + 1 - 4 x ( 2 x - 1 )}{2 x}, - \frac{1 + 1 - 4 x ( 2 x - 1 )}{2 x}, \frac{1 - 1 - 4 x ( 2 x - 1 )}{2 x}, - \frac{1 - 1 - 4 x ( 2 x - 1 )}{2 x}

Solution steps

y = \frac{1 + x ^{2}}{2 + x ^{4}}

Replace

x

with

y

x = \frac{1 + y ^{2}}{2 + y ^{4}}

Solve for

y, x = \frac{1 + y ^{2}}{2 + y ^{4}}

\frac{1 + 1 - 4 x ( 2 x - 1 )}{2 x}, - \frac{1 + 1 - 4 x ( 2 x - 1 )}{2 x}, \frac{1 - 1 - 4 x ( 2 x - 1 )}{2 x}, - \frac{1 - 1 - 4 x ( 2 x - 1 )}{2 x}

(cos (9 x))^{x}

f (x) = (5)^{x}

f (x) = x^{3} + x^{2} + x

y = - 5 x + 6

sin (arccos (4 x))

What is the inverse of f(x)=((1+x^2))/((2+x^4)) ?
The inverse of f(x)=((1+x^2))/((2+x^4)) is