What is the asymptotes of y=(x^2+1)/(x^2-1) ?

The asymptotes of y=(x^2+1)/(x^2-1) is Vertical: x=-1,x=1,Horizontal: y=1

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asymptotes of y=(x^2+1)/(x^2-1)

asymptotes

y = \frac{x ^{2} + 1}{x ^{2} - 1}

Vertical : x = - 1, x = 1, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 1

f (x) = 6 x + 9

f (x) = - x - 2 + 1

f (x) = \frac{2 x}{5 x - 1}

2 sin (x)

f (x) = \frac{x - 4}{x ( x - 4 )}

What is the asymptotes of y=(x^2+1)/(x^2-1) ?
The asymptotes of y=(x^2+1)/(x^2-1) is Vertical: x=-1,x=1,Horizontal: y=1