What is the derivative of-3cos(2x+4/3 pi) ?

The derivative of-3cos(2x+4/3 pi) is -3(sin(2x)+sqrt(3)cos(2x))

What is the first derivative of-3cos(2x+4/3 pi) ?

The first derivative of-3cos(2x+4/3 pi) is -3(sin(2x)+sqrt(3)cos(2x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- 3 cos (2 x + \frac{4}{3} π))

- 3 (sin (2 x) + 3 cos (2 x))

Solution steps

\frac{d}{d x} (- 3 cos (2 x + \frac{4}{3} π))

Simplify

- 3 cos (2 x + \frac{4}{3} π) : - 3 (- \frac{1}{2} cos (2 x) + \frac{3}{2} sin (2 x))

= \frac{d}{d x} (- 3 (- \frac{1}{2} cos (2 x) + \frac{3}{2} sin (2 x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (- \frac{1}{2} cos (2 x) + \frac{3}{2} sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - 3 (- \frac{d}{d x} (\frac{1}{2} cos (2 x)) + \frac{d}{d x} (\frac{3}{2} sin (2 x)))

\frac{d}{d x} (\frac{1}{2} cos (2 x)) = - sin (2 x)

\frac{d}{d x} (\frac{3}{2} sin (2 x)) = 3 cos (2 x)

= - 3 (- (- sin (2 x)) + 3 cos (2 x))

Simplify

= - 3 (sin (2 x) + 3 cos (2 x))

y = 3 csc (x + π) + 5

f (x) = 5 x^{2} - 6

f (x) = 5 x^{2} - 9

y = (x - 1) (x + 4)

f (x) = \frac{x ^{2}}{x ^{2} + x - 12}

What is the derivative of-3cos(2x+4/3 pi) ?
The derivative of-3cos(2x+4/3 pi) is -3(sin(2x)+sqrt(3)cos(2x))
What is the first derivative of-3cos(2x+4/3 pi) ?
The first derivative of-3cos(2x+4/3 pi) is -3(sin(2x)+sqrt(3)cos(2x))