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Popular >

h(x)=(2x^2)/(x^2-1)

Solution

h (x) = \frac{2 x ^{2}}{x ^{2} - 1}

Solution

Domain : x < - 1 or - 1 < x < 1 or x > 1

Range : f (x) \leq 0 or f (x) > 2

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - 1, x = 1, Horizontal y = 2

Extreme Points : Maximum (0, 0)

+1

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Range : (- \infty, 0] \cup (2, \infty)

Solution steps

Domain of

\frac{2 x ^{2}}{x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

Range of

\frac{2 x ^{2}}{x ^{2} - 1} : f (x) \leq 0 or f (x) > 2

Axis interception points of

\frac{2 x ^{2}}{x ^{2} - 1} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{2 x ^{2}}{x ^{2} - 1} :

Vertical

: x = - 1, x = 1,

Horizontal

: y = 2

Extreme Points of

\frac{2 x ^{2}}{x ^{2} - 1} :

Maximum

(0, 0)

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y = x^{3} - 6 x^{2} + 11 x - 6

y = - 4 - 7 cos (12 x)

f(x)=-2x^2-8x+1

f (x) = - 2 x^{2} - 8 x + 1

Frequently Asked Questions (FAQ)

What is the h(x)=(2x^2)/(x^2-1) ?
The h(x)=(2x^2)/(x^2-1) is