What is the f(n)=(2^{n+3}-2^n+7)/(2^{n+1)-2^n+1} ?

The f(n)=(2^{n+3}-2^n+7)/(2^{n+1)-2^n+1} is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(n)=(2^{n+3}-2^n+7)/(2^{n+1)-2^n+1}

f (n) = \frac{2 ^{n + 3} - 2 ^{n} + 7}{2 ^{n + 1} - 2 ^{n} + 1}

Domain : - \infty < n < \infty

Range : False for all f (x) \in R

Y Intercepts : (0, 7)

Asymptotes : Horizontal y = \frac{2 ^{n + 3} - 2 ^{n} + 7}{2 ^{n + 1} - 2 ^{n} + 1}

Extreme Points : None

Interval Notation

Domain : (- \infty, \infty)

Range :

Solution steps

Domain of

\frac{2 ^{n + 3} - 2 ^{n} + 7}{2 ^{n + 1} - 2 ^{n} + 1} : - \infty < n < \infty

Range of

\frac{2 ^{n + 3} - 2 ^{n} + 7}{2 ^{n + 1} - 2 ^{n} + 1} :

False for all

f (x) \in R

Axis interception points of

\frac{2 ^{n + 3} - 2 ^{n} + 7}{2 ^{n + 1} - 2 ^{n} + 1} :

Y Intercepts

: (0, 7)

Asymptotes of

\frac{2 ^{n + 3} - 2 ^{n} + 7}{2 ^{n + 1} - 2 ^{n} + 1} :

Horizontal

: y = \frac{2 ^{n + 3} - 2 ^{n} + 7}{2 ^{n + 1} - 2 ^{n} + 1}

Extreme Points of

\frac{2 ^{n + 3} - 2 ^{n} + 7}{2 ^{n + 1} - 2 ^{n} + 1} :

None

f (x) = 3 x - 8 + x^{3} - 11 x^{2}

y = x^{3} - 2 x + 4

y = x^{2} + 7 x + 2

y = x^{2} + 7 x + 3

f (x) = \frac{1}{5 x + 6}

What is the f(n)=(2^{n+3}-2^n+7)/(2^{n+1)-2^n+1} ?
The f(n)=(2^{n+3}-2^n+7)/(2^{n+1)-2^n+1} is