What is the f(x)=log_{2}(x+1)+log_{2}(x-1) ?

The f(x)=log_{2}(x+1)+log_{2}(x-1) is

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f(x)=log_{2}(x+1)+log_{2}(x-1)

f (x) = lo g_{2} (x + 1) + lo g_{2} (x - 1)

Domain : x > 1

Range : - \infty < f (x) < \infty

X Intercepts : (2, 0)

Asymptotes : Vertical x = 1

Extreme Points : None

Interval Notation

Domain : (1, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

lo g_{2} (x + 1) + lo g_{2} (x - 1) : x > 1

Range of

lo g_{2} (x + 1) + lo g_{2} (x - 1) : - \infty < f (x) < \infty

Axis interception points of

lo g_{2} (x + 1) + lo g_{2} (x - 1) :

X Intercepts

: (2, 0)

Asymptotes of

lo g_{2} (x + 1) + lo g_{2} (x - 1) :

Vertical

: x = 1

Extreme Points of

lo g_{2} (x + 1) + lo g_{2} (x - 1) :

None

f (x) = - 8 x + 6 - 5 x^{3} + x^{4} - 6 x^{2}

f (x) = 3 sin^{2} (x) cos^{2} (x)

y = x^{2} - 4 x + 11

y = lo g_{2} (x) + 3

f (x) = e^{- x} + 4

What is the f(x)=log_{2}(x+1)+log_{2}(x-1) ?
The f(x)=log_{2}(x+1)+log_{2}(x-1) is