What is the y= 1/(\sqrt[3]{x-2)}+sqrt(x(3-x)) ?

The y= 1/(\sqrt[3]{x-2)}+sqrt(x(3-x)) is

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y= 1/(\sqrt[3]{x-2)}+sqrt(x(3-x))

Domain : 0 \leq x < 2 or 2 < x \leq 3

Range : f (x) \leq 0.41437 \dots or f (x) \geq 1

Asymptotes : Vertical x = 2

Interval Notation

Domain : [0, 2) \cup (2, 3]

Range : (- \infty, 0.41437 \dots] \cup [1, \infty)

Solution steps

Domain of

Range of

Axis interception points of

X Intercepts

: (0.25049 \dots, 0), (1.69595 \dots, 0),

Y Intercepts

Asymptotes of

Vertical

: x = 2

Extreme Points of

Minimum

Maximum

(1.01625 \dots, 0.41437 \dots),

Minimum

(3, 1)

f (x) = \frac{x ^{2} + 1}{x ^{2} - 16}

f (x) = (x - 1) (x + 2)^{2}

f (x) = \frac{cot ( x )}{ln ( 10 )}

y = - 5 x^{3} - 5 x^{2} + 210 x

f (x) = x^{2} - 12

What is the y= 1/(\sqrt[3]{x-2)}+sqrt(x(3-x)) ?
The y= 1/(\sqrt[3]{x-2)}+sqrt(x(3-x)) is