What is the domain of (x^2+x-12)/(x-3) ?

The domain of (x^2+x-12)/(x-3) is x 3

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domain of (x^2+x-12)/(x-3)

domain

\frac{x ^{2} + x - 12}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

y + 1 = 2 x

f (x) = x + 13

e^{x + 2} - 2

f (x) = - \frac{2}{x + 3}

f (x) = (x + 4)^{3}

What is the domain of (x^2+x-12)/(x-3) ?
The domain of (x^2+x-12)/(x-3) is x<3\lor x>3