What is the d/(dt)(4+2cos((pit)/3)) ?

The d/(dt)(4+2cos((pit)/3)) is -(2pi)/3 sin((pit)/3)

What is the first d/(dt)(4+2cos((pit)/3)) ?

The first d/(dt)(4+2cos((pit)/3)) is -(2pi)/3 sin((pit)/3)

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\frac{d}{d t} (4 + 2 cos (\frac{π t}{3}))

- \frac{2 π}{3} sin (\frac{π t}{3})

Solution steps

\frac{d}{d t} (4 + 2 cos (\frac{π t}{3}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (4) + \frac{d}{d t} (2 cos (\frac{π t}{3}))

\frac{d}{d t} (4) = 0

\frac{d}{d t} (2 cos (\frac{π t}{3})) = - \frac{2 π}{3} sin (\frac{π t}{3})

= 0 - \frac{2 π}{3} sin (\frac{π t}{3})

Simplify

= - \frac{2 π}{3} sin (\frac{π t}{3})

y = 3^{4 - x} + 1

f (a) = a^{\frac{5}{3}}

f (x) = sin (x) tan (\frac{x}{2})

f (x) = \frac{sin ( 3 x )}{2 x}

f (x) = 20 x^{6}

What is the d/(dt)(4+2cos((pit)/3)) ?
The d/(dt)(4+2cos((pit)/3)) is -(2pi)/3 sin((pit)/3)
What is the first d/(dt)(4+2cos((pit)/3)) ?
The first d/(dt)(4+2cos((pit)/3)) is -(2pi)/3 sin((pit)/3)