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Popular >

midpoint (9,3),(5,-4)

Solution

midpoint

(9, 3), (5, - 4)

Solution

(7, - \frac{1}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (9, 3), (x_{2}, y_{2}) = (5, - 4)

= (\frac{5 + 9}{2}, \frac{- 4 + 3}{2})

Refine

= (7, - \frac{1}{2})

Popular Examples

domain of f(x)=(x+4)/(x^2+3x+2)domain

f (x) = \frac{x + 4}{x ^{2} + 3 x + 2}

inflection x^2+3 inflection points

x^{2} + 3

inverse of f(x)= 3/(x+8)inverse

f (x) = \frac{3}{x + 8}

inverse of f(x)=(x+16)/(x-13)inverse

f (x) = \frac{x + 16}{x - 13}

inverse of f(x)=log_{3}(x+7)inverse

f (x) = lo g_{3} (x + 7)

Frequently Asked Questions (FAQ)

What is the midpoint (9,3),(5,-4) ?
The midpoint (9,3),(5,-4) is (7,-1/2)