What is the domain of 1/(sqrt(x^2-7x+12)) ?

The domain of 1/(sqrt(x^2-7x+12)) is x 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(sqrt(x^2-7x+12))

domain

\frac{1}{x ^{2} - 7 x + 12}

x < 3 or x > 4

Interval Notation

(- \infty, 3) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 3 or x \geq 4

Find undefined (singularity) points:

x = 4, x = 3

Combine real regions and undefined points for final function domain

x < 3 or x > 4

f (x) = \frac{3 x ^{3} - 6 x ^{2}}{x - 2}

- 5 cos (3 x)

f (x) = 5 tan (x + \frac{π}{6})

f (x) = \frac{x + 6}{x ^{2} + 5 x}

x^{5} - 3 x^{4} + 3 x^{3} - 5 x^{2} + 12

What is the domain of 1/(sqrt(x^2-7x+12)) ?
The domain of 1/(sqrt(x^2-7x+12)) is x<3\lor x>4