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Popular >

h(x)=-7x^2+10x-5

Solution

h (x) = - 7 x^{2} + 10 x - 5

Solution

Domain : - \infty < x < \infty

Range : f (x) \leq - \frac{10}{7}

Y Intercepts : (0, - 5)

Vertex : Maximum (\frac{5}{7}, - \frac{10}{7})

Inverse : - \frac{- 5 + - 7 x - 10}{7}, \frac{- 7 x - 10 + 5}{7}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, - \frac{10}{7}]

Solution steps

Domain of

- 7 x^{2} + 10 x - 5 : - \infty < x < \infty

Range of

- 7 x^{2} + 10 x - 5 : f (x) \leq - \frac{10}{7}

Axis interception points of

- 7 x^{2} + 10 x - 5 :

Y Intercepts

: (0, - 5)

Vertex of

- 7 x^{2} + 10 x - 5 :

Maximum

(\frac{5}{7}, - \frac{10}{7})

Inverse of

- 7 x^{2} + 10 x - 5 : - \frac{- 5 + - 7 x - 10}{7}, \frac{- 7 x - 10 + 5}{7}

Popular Examples

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f (x) = 4 x - 16

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f (x) = \frac{3 x ^{2}}{x ^{2} + 2 x - 8}

f(x)=\sqrt[3]{2x+4}

Frequently Asked Questions (FAQ)

What is the h(x)=-7x^2+10x-5 ?
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