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Popular >

y=ln((x+1)/(x^2+1))

Solution

y = ln (\frac{x + 1}{x ^{2} + 1})

Solution

Domain : x > - 1

Range : f (x) \leq ln (\frac{1}{2} + \frac{1}{2})

X Intercepts : (1, 0), (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - 1

Extreme Points : Maximum (2 - 1, - ln (22 - 2))

+1

Interval Notation

Domain : (- 1, \infty)

Range : (- \infty, ln (\frac{1}{2} + \frac{1}{2})]

Solution steps

Domain of

ln (\frac{x + 1}{x ^{2} + 1}) : x > - 1

Range of

ln (\frac{x + 1}{x ^{2} + 1}) : f (x) \leq ln (\frac{1}{2} + \frac{1}{2})

Axis interception points of

ln (\frac{x + 1}{x ^{2} + 1}) :

X Intercepts

: (1, 0), (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

ln (\frac{x + 1}{x ^{2} + 1}) :

Vertical

: x = - 1

Extreme Points of

ln (\frac{x + 1}{x ^{2} + 1}) :

Maximum

(2 - 1, - ln (22 - 2))

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f (x) = x^{3} - 3 x^{2} + 24 x + 32

Frequently Asked Questions (FAQ)

What is the y=ln((x+1)/(x^2+1)) ?
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