What is the inverse of f(x)=(ln(3x))/(8+ln(3x)) ?

The inverse of f(x)=(ln(3x))/(8+ln(3x)) is (e^{-(8x)/(x-1)})/3

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inverse of f(x)=(ln(3x))/(8+ln(3x))

inverse

f (x) = \frac{ln ( 3 x )}{8 + ln ( 3 x )}

\frac{e ^{- \frac{8 x}{x - 1}}}{3}

Solution steps

y = \frac{ln ( 3 x )}{8 + ln ( 3 x )}

Replace

x

with

y

x = \frac{ln ( 3 y )}{8 + ln ( 3 y )}

Solve for

y, x = \frac{ln ( 3 y )}{8 + ln ( 3 y )}

\frac{e ^{- \frac{8 x}{x - 1}}}{3}

f (x) = 9 sin (x - 5) + 8

f (x) = \frac{2 x - 6}{4}

f (x) = x^{2} - 12 x + 11

f (x) = \frac{2 x + 1}{4 x - 1}

f (x) = 3 x^{2} - 2 x + 1

What is the inverse of f(x)=(ln(3x))/(8+ln(3x)) ?
The inverse of f(x)=(ln(3x))/(8+ln(3x)) is (e^{-(8x)/(x-1)})/3