What is the inverse of ln((s-2)/(s+2)) ?

The inverse of ln((s-2)/(s+2)) is (-2-2e^s)/(e^s-1)

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inverse of ln((s-2)/(s+2))

inverse

ln (\frac{s - 2}{s + 2})

\frac{- 2 - 2 e ^{s}}{e ^{s} - 1}

Solution steps

y = ln (\frac{s - 2}{s + 2})

Replace

s

with

y

s = ln (\frac{y - 2}{y + 2})

Solve for

y, s = ln (\frac{y - 2}{y + 2})

\frac{- 2 - 2 e ^{s}}{e ^{s} - 1}

\frac{x ^{2} - 2 x - 1}{x + 1}

(5.7) (- 1)

cos (2 t)

(0, - 3), (3, 0)

What is the inverse of ln((s-2)/(s+2)) ?
The inverse of ln((s-2)/(s+2)) is (-2-2e^s)/(e^s-1)