What is the inverse of f(x)=(bx+3)/(3x-7) ?

The inverse of f(x)=(bx+3)/(3x-7) is (3+7x)/(3x-b)

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inverse of f(x)=(bx+3)/(3x-7)

inverse

f (x) = \frac{b x + 3}{3 x - 7}

\frac{3 + 7 x}{3 x - b}

Solution steps

y = \frac{b x + 3}{3 x - 7}

Replace

x

with

y

x = \frac{b y + 3}{3 y - 7}

Solve for

y, x = \frac{b y + 3}{3 y - 7}

\frac{3 + 7 x}{3 x - b}

f (x) = \frac{x}{x ^{2} - 4}

g (x) = (x - 9)^{2}

f (x) = x - 3 + 9

f (x) = \frac{x - 2}{6}

f (x) = \frac{1}{6} x - 3

What is the inverse of f(x)=(bx+3)/(3x-7) ?
The inverse of f(x)=(bx+3)/(3x-7) is (3+7x)/(3x-b)