What is the inverse of f(x)=((x-1)^2)/(81) ?

The inverse of f(x)=((x-1)^2)/(81) is 9sqrt(x)+1,-9sqrt(x)+1

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inverse of f(x)=((x-1)^2)/(81)

inverse

f (x) = \frac{( x - 1 ) ^{2}}{81}

9 x + 1, - 9 x + 1

Solution steps

y = \frac{( x - 1 ) ^{2}}{81}

Replace

x

with

y

x = \frac{( y - 1 ) ^{2}}{81}

Solve for

y, x = \frac{( y - 1 ) ^{2}}{81}

9 x + 1, - 9 x + 1

f (x) = 1.8 x + 32

g (x) = \frac{3 x + 5}{8}

(x + 1)^{2} - 2

F (x) = 5 - 2^{(- x)}

f (x) = cos (x - π) + 2

What is the inverse of f(x)=((x-1)^2)/(81) ?
The inverse of f(x)=((x-1)^2)/(81) is 9sqrt(x)+1,-9sqrt(x)+1