What is the inverse of f(x)=(3x+1)/(4x-2) ?

The inverse of f(x)=(3x+1)/(4x-2) is (1+2x)/(4x-3)

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inverse of f(x)=(3x+1)/(4x-2)

inverse

f (x) = \frac{3 x + 1}{4 x - 2}

\frac{1 + 2 x}{4 x - 3}

Solution steps

y = \frac{3 x + 1}{4 x - 2}

Replace

x

with

y

x = \frac{3 y + 1}{4 y - 2}

Solve for

y, x = \frac{3 y + 1}{4 y - 2}

\frac{1 + 2 x}{4 x - 3}

f (x) = 5 (x + 3)^{3} - 2

f (x) = \frac{2 x}{3 x + 7}

f (x) = 3^{x + 2} - 1

f (x) = \frac{2 x + 5}{x + 7}

f (x) = \frac{1 - e ^{2 x}}{2 + e ^{2 x}}

What is the inverse of f(x)=(3x+1)/(4x-2) ?
The inverse of f(x)=(3x+1)/(4x-2) is (1+2x)/(4x-3)