What is the inverse of f(x)=3(x+4)^2-2 ?

The inverse of f(x)=3(x+4)^2-2 is sqrt((x+2)/3)-4,-sqrt((x+2)/3)-4

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inverse of f(x)=3(x+4)^2-2

inverse

f (x) = 3 (x + 4)^{2} - 2

\frac{x + 2}{3} - 4, - \frac{x + 2}{3} - 4

Solution steps

y = 3 (x + 4)^{2} - 2

Replace

x

with

y

x = 3 (y + 4)^{2} - 2

Solve for

y, x = 3 (y + 4)^{2} - 2

\frac{x + 2}{3} - 4, - \frac{x + 2}{3} - 4

f (x) = 8 x - 3

x^{2} - 3 x - 10

f (x) = 2 \cdot 3^{x} + 9^{x} + 5

f (x) = \frac{x - 1}{3 - 2 x}

f (x) = 6 x + 8

What is the inverse of f(x)=3(x+4)^2-2 ?
The inverse of f(x)=3(x+4)^2-2 is sqrt((x+2)/3)-4,-sqrt((x+2)/3)-4