What is the inverse of f(x)=3(x+2)^2-5 ?

The inverse of f(x)=3(x+2)^2-5 is sqrt((x+5)/3)-2,-sqrt((x+5)/3)-2

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inverse of f(x)=3(x+2)^2-5

inverse

f (x) = 3 (x + 2)^{2} - 5

\frac{x + 5}{3} - 2, - \frac{x + 5}{3} - 2

Solution steps

y = 3 (x + 2)^{2} - 5

Replace

x

with

y

x = 3 (y + 2)^{2} - 5

Solve for

y, x = 3 (y + 2)^{2} - 5

\frac{x + 5}{3} - 2, - \frac{x + 5}{3} - 2

f (x) = e^{x} - 3

f (x) = x^{2} - 2 x - 8, x > 1

f (x) = \frac{4}{9 x}

f (x) = \frac{2}{5 x}

y = x^{2} + 1

What is the inverse of f(x)=3(x+2)^2-5 ?
The inverse of f(x)=3(x+2)^2-5 is sqrt((x+5)/3)-2,-sqrt((x+5)/3)-2