What is the inverse of f(x)=x^2-2,x<= 0 ?

The inverse of f(x)=x^2-2,x<= 0 is sqrt(x+2),-sqrt(x+2)

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inverse of f(x)=x^2-2,x<= 0

inverse

f (x) = x^{2} - 2, x \leq 0

x + 2, - x + 2

Solution steps

y = x^{2} - 2

Replace

x

with

y

x = y^{2} - 2

Solve for

y, x = y^{2} - 2

x + 2, - x + 2

lo g_{2} (x) - 3

\frac{2}{x ^{2} + 2}

f (x) = \frac{2 x ^{2} + 4}{2 x ^{2} - 7 x - 15}

f (x) = \frac{1}{x} + 4

8 x + 2 y = 2

What is the inverse of f(x)=x^2-2,x<= 0 ?
The inverse of f(x)=x^2-2,x<= 0 is sqrt(x+2),-sqrt(x+2)