What is the inverse of ln(3x-5)-ln(x+9)+5 ?

The inverse of ln(3x-5)-ln(x+9)+5 is (-5e^5-9e^x)/(e^x-3e^5)

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inverse of ln(3x-5)-ln(x+9)+5

inverse

ln (3 x - 5) - ln (x + 9) + 5

\frac{- 5 e ^{5} - 9 e ^{x}}{e ^{x} - 3 e ^{5}}

Solution steps

y = ln (3 x - 5) - ln (x + 9) + 5

Replace

x

with

y

x = ln (3 y - 5) - ln (y + 9) + 5

Solve for

y, x = ln (3 y - 5) - ln (y + 9) + 5

\frac{- 5 e ^{5} - 9 e ^{x}}{e ^{x} - 3 e ^{5}}

f (x) = x^{2} + x - 6

f (x) = \frac{5 x - 1}{3}

f (x) = \frac{x - 1}{1 + 4 x}

y = \frac{x + 1}{x}

f (x) = \frac{2}{3} x - 6

What is the inverse of ln(3x-5)-ln(x+9)+5 ?
The inverse of ln(3x-5)-ln(x+9)+5 is (-5e^5-9e^x)/(e^x-3e^5)