What is the inverse of f(x)=2^{x+1}-3 ?

The inverse of f(x)=2^{x+1}-3 is (ln(x+3))/(ln(2))-1

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inverse of f(x)=2^{x+1}-3

inverse

f (x) = 2^{x + 1} - 3

\frac{ln ( x + 3 )}{ln ( 2 )} - 1

Solution steps

y = 2^{x + 1} - 3

Replace

x

with

y

x = 2^{y + 1} - 3

Solve for

y, x = 2^{y + 1} - 3

\frac{ln ( x + 3 )}{ln ( 2 )} - 1

f (x) = arctan (x)

f (x) = \frac{3 x - 7}{4 x + 3}

f (x) = \frac{x ^{2} - 2}{x}

f (x) = \frac{( 2 x + 5 )}{x - 7}

f (x) = 2^{2 x}

What is the inverse of f(x)=2^{x+1}-3 ?
The inverse of f(x)=2^{x+1}-3 is (ln(x+3))/(ln(2))-1